Ajar contains 6 red balls and 5 blue balls. two balls are drawn at random from the hat without replacement. what is the probability that both the balls drawn are blue?

2/11

Step-by-step explanation:

We are going to solve this by using a tree diagram. It makes it a lot easier. The tree diagram is attached below.

From the tree tree diagram,

Probability of picking a blue ball at the first draw is 5/11

Prbability of picking ble at the second draw, if the balls are picked without replacement is 4/10

Probability of drawing two blue balls are;

P(B,B) = 5/11 × 4/10 = 20/ 110

Divide the numerator and denominator by 10

P(B,B) = 2/11

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.