Mathematics, 21.01.2020 05:31 Dillpickle3322
Consider a purely probabilistic game that you have the opportunity to play. each time you play there are n potential outcomes x1, x2, xn (each of which is a specified gain or loss of euros). these outcomes x1, x2, xn occur with the probabilities p1, p2, pn respectively (where p1 + p2 + + pn = 1.0 and 0 < = pi < = 1 for each i). positive xi values mean a gain of |xi| euros and negative values mean a loss of |xi| euros. assume that x1, x2, xn and p1, p2, pn are all known quantities. furthermore, assume that each play of the game takes up one hour of your time, and that only you can play the game (you can't hire someone to play for you). let m be the game's expected value. that is, m = p1*x1 + p2*x2 + + pn*xn. let s be the game's standard deviation. that is, s = squareroot( p1 * (x1 - m)^2 + p2 * (x2 - m)^2 + + pn * (xn - m)^2 ).
Answers: 3
Mathematics, 21.06.2019 21:00, animexcartoons209
With alll of except for the 2 that i did already
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Mathematics, 21.06.2019 21:00, sjackson0625p8w1a0
Me! i will mark you brainliest if you are right and show your i don't get polynomials and all the other stuff. multiply and simplify.2x(^2)y(^3)z(^2) · 4xy(^4)x(^2)show your
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Mathematics, 21.06.2019 23:40, tanviknawale
The function f(x)= -(x+5)(x+1) is down. what is the range of the function?
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Consider a purely probabilistic game that you have the opportunity to play. each time you play there...
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