Ms. jamison plans to invest $3,800 in two accounts for one year. the first account earns a yearly interest of 3.5%. the second account earns a yearly interest of 6%. how much money does ms. jamison need to invest in the second account in order to earn $188 in interest from both accounts? show all of your work.

The Amount investment in second account is $2200

Step-by-step explanation:

Given as :

Total money invested in two accounts =  $3800

The time period of investment = t = 1 year

Let The amount investment in first account = $p

Let The amount investment in second account = $3800 - $p

The rate of interest for first account = = 3.5%

The rate of interest for second account = = 6%

The total interest earn from both account = s.i = $188

Let The interest earn from first account =

Let The interest earn from second account =

Now, From simple interest method

Simple interest =

For First account

=

i.e =

Again

For second account

=

=

Since  total interest earn from both account = s.i = $188

i.e s.i = +

Or, s.i = +

Or, $188 = +

Or, 188 × 100 = 3.5 p + 22800 - 6 p

Or, 6 p - 3.5 p = 22800 - 18800

Or, 2.5 p = 4000

∴ p =

i.e p = $1600

So, The amount investment in first account = p = $1600

So, The amount investment in second account = $3800 - $p

i.e The amount investment in second account = $3800 - $1600

Or, The amount investment in second account = $2200

Hence, The Amount investment in second account is $2200  Answer

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