Find hcf of 308 and 210 and express it in the form of 310m + 210n and find m and n

Hcf value for the given numbers is 14.

The value of m and n is -2 and 3.

The form is 308(-2)+210(3).

Step-by-step explanation:

To find the hcf:

Step 1: Divide the largest number by the smallest.

308÷210=1+98.

Here 1 is the quotient and 98 is the reminder.

Step 2: Divide the smaller number by the reminder.

210÷98=2+14.

Step 3: Divide the smallest number previous step by its reminder.

98÷14=7+0.

At this step, the remainder is zero, so we stop:

14 is the number we were looking for, the last remainder that is not zero.

∴ 14 is the hcf.

Now we have to find m and n.

To find 308m+210n form,

Write the steps in backwards for the reminder.

For 13 as reminder, 13 = 210-(98×2).

For 98 as reminder 98=308-(210×1).

replace the value of 98,

13=210-((308-(210×1)×2).

13=210-(308×2)+(210×2).

13=(210×3)-(308×2).

13=(-308×2)+(210×3).

since the 308 is given in positive rewrite the form as,

=308(-2)+210(3).

∴ m = -2 and n=3.

over the argument its not good to fight.

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: