Solve sa = πrs + π r2 for s
a) -r
b) sa + r
c)
sa
π2r3
d)
sa - πr2
πr

D) SA - πr²

.         πr

Step-by-step explanation:

Rearrange the equation to isolate s (separate it from everything else).

SA = πrs + πr²      s is in πrs, so start by moving the other term: πr²

SA - πr² = πrs     Subtract πr² from both sides. It cancels out on the right

(SA - πr²)/πr = s       Divide both sides by πr

s = SA - πr²

.         πr

the answer is su.k.my? ? co.kc

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: