In the year 2000, the average cost of a computer could be modeled by the equation c = -5t2 + 750, where t is the number of years since 2000. by the year 2008 the average cost had changed, so it could be modeled by the equation c = -10t2 + 500. find the difference in the average costs for a computer between 2008 and 2000.

Step-by-step explanation:

Given:

The average cost of a computer in the year 2000 is given as:

The average cost of a computer in the year 2008 is given as:

Now, the difference in average cost between the years 2008 and 2000 can be calculated by subtracting the average cost in 2000 from the average cost in 2008.

Framing in equation form, we get:

Difference in average cost (ΔC) is given as:

Therefore, the difference in the costs for a computer between 2008 and 2000 is

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.