Find the values of m and n so that the polynomial p(z)=z^3-mz^2-13z+n has (z-1) and (z+3) as factors
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pls answee fast i have exam tomo

m = 3, n = 15.

Step-by-step explanation:

As the factors are z-1 and z+3 then z = 1 and z = -3 are zeroes of the function so substituting for z = 1 and z = -3:

1^3 - 1m - 13(1) + n = 0

n - m = 12 (a)

(-3)^3 - 9m + 39 + n = 0

n - 9m = -12 (b).

Subtract:  (a) - (b):

8m = 24

m = 3.

Substituting m = 3 in equation (a):

n - 3 = 12

n = 15.

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)