Find cos(20°)+2cos^2 (80°)
me pls.

i did not understand your question

Step-by-step explanation:

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Step-by-step explanation:

2cos²(80°)=1+cos(2(80°))

From trigonometry identity that states: cos2θ=2cos²θ-1

And from that we have: 2cos²θ=1+cos2θ

which makes 2cos²(80°)=1+cos(2(80°))

                                      =1+cos(160°)

From the quadrant table, cosine is negative on the second quadrant i.e.

cos(180°-θ)=-cosθ

Therefore, cos(160°)=cos(180°-20°)=-cos(20°)

Going back to the original question,

 cos(20°)+2cos²(80°)=cos(20°)+1+cos(160°)

                                 =cos(20°)+1+(-cos(20°))

                                 =cos(20°)+1-cos(20°)

                                 =cos(20°)-cos(20°)+1

                                 =1.

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step-by-step explanation: