Abox contains 5 plain pencils and 5 pens. a second box contains 3 pencils and 1 crayon. one item from each box is chosen at random what is the probability that a pen from the first box and a crayon from the second box are selected

0.75

Step-by-step explanation:

OK maths is always about looking at thing simply, one by one.

Let us look at the first box. There r 5 pencils and 5 pens. So what is the probability of getting a pen from first box? First there r total of 10 things in the first box. Probability of getting a pen from that box? It is 5÷10 which is number of favorable pitcomes to pen ÷ total number of outcomes which is 10.

Now the second box. There r 1 crayon and 3 pencils. Total of 4 outcomes(3plus1).

So probablilty of getting a crayon from second box is number of favorable outcomes to crayon ÷ total number of outcomes which is 4=1÷4

Now add the first probability of getting a pen from first box and probability of getting a crayon from second box. This is because it's given in the question to find out the probability of getting a pen AND a crayon which means first find the probability of pen and crayon seperatly and then add them.

Now add those 2 probabilities together which is 5÷10 plus 1÷4 then we will get 0.75.

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total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98