Acoin is tossed 4 times. what is the probability if getting 2 heads, 2 tails?

11/16

Step-by-step explanation:

P(THHH)=4!3!∗(12)4=416P

(THHH)=4!3!∗(12)4=416, we are multiplying by 4!/3! since THHH scenario can occur in number of ways: THHH, HTHH , HHTH, or HHHT (notice that 4!/3! basically gives number of arrangements of 4 letters THHH out of which 3 H's are identcal).

P(T≥2)=1−(1/16+4/16)=11/16

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph