Recall the equation for a circle with center (h, k) and radius r. at what point in the first quadrant does the line with equation y
=2.5x+2 intersect the circle with radius 4 and center (0, 2)?

At point (1.486, 5.714)

Step-by-step explanation:

The equation of the circle with radius 4 and center at (0, 2) is:

and we want to know where in the 1st quadrant does it intersect with line

To find the point of intersection we put the value of   into the equation of the circle:

and since we only concerned with the 1st quadrant we take the positive value of which is the x coordinate of intersection.

The y coordinate is found by putting this x value into either the circle equation or the line equation ; we choose the line equation because it is easier to work with.

Thus we have the point of intersection

the first question mark is 6 and the second question mark is 26 (the square root)

step-by-step explanation:

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6