Write (9+6/) - (1+3/) as a complex number in a standard form

(9 + 6i) - (1 + 3i) as a complex number in standard form is 8 + 3i

Solution:

Given that we have to write (9 + 6i) - (1 + 3i) as a complex number in standard form

A Complex Number is a combination of real Number and an imaginary Number

The standard form of complex number is:

a + bi

Where "a" and "b" are real numbers and i is the unit imaginary number

Given expression is:

(9 + 6i) - (1 + 3i)

Remove the parenthesis and solve the expression

9 + 6i - 1 - 3i

Combine the like terms

9 + 6i - 1 - 3i = 8 + 3i

Thus the given expression as complex number in standard form is 8 + 3i

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

step-by-step explanation:

20-2= what