Find the limit of the function algebraically.
limit as x approaches five of quantity x squared minus twenty five divided by quantity x minus five.

Factor x^2 - 25 as
x^2-5^2
= (x+5)(x-5)

so,
(x^2-25)/(x-5) = (x+5)(x-5)/(x-5) = x+5

limit of x->5 of (x+5)
can be just found by plugging in x = 5.

lim x->5 (x+5) = 5+5 = 10.

so the limit value = 10

Period is the time it takes for one “cycle” to complete. in the parent sine function, period is 2*pi since sin(0) = 0, sin(pi/2) = 1, sin(pi) = 0, sin(3pi/2) = -1, and sin(2pi) = 0. at that point, the sequence repeats itself. i’m not sure if your graph is similar to the sine function since you didn’t provide a picture, but you can find the period by looking at a graph.