Marcos and 16 coins in nickels and quarters. he has 3 more quarters than nickels. write the system of equations and solve to find the number of nickels and the number of quarters marcos has.

There is typo error in the question. The total number of coins will be 15.

There are 6 nickels and 9 quarters.

Step-by-step explanation:

Let 'n' be number of nickels and 'q' be number of quarters.

Given:

Marcos has 15 coins in total.

Marcos has 3 more quarters than nickels.

So, as per question,

Total coins = Number of nickels + Number of quarters.

Framing in equation form, we get:

------------------ (1)

Now, Marcos has 3 more quarters than nickels. So, framing in equation form, we get:

-------------------- (2)

Substitute the value of 'q' from equation (2) to equation (1). This gives,

Therefore, the number of nickels are 6.

Now, number of quarters = 6 + 3 = 9

So, there are 6 nickels and 9 quarters.

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

12

step-by-step explanation:

12 + 5 = 17

12x2=24

24-7=17