Banana republic at the orlando, florida, outlet store sells casual jeans for $40 and dress jeans for $60. if customers bought 5 times more casual than dress jeans and last month's sales totaled $6,500, how many of each type of jeans were sold?

Banana Republic at the Orlando, Florida, outlet store sold 125 casual jeans and 25 Dress jeans last month.

Step-by-step explanation:

Given:

Cost of casual jeans = $40

Cost of Dress jeans = $60

Totaled amount of sales last month $6500

We need to find the number of casual jeans and number of dress jeans sold last month.

Solution:

Let the number of casual jeans sold be 'x'.

Also Let the number of dress jeans sold be 'y'.

Also Given:

If customers bought 5 times more casual than dress jeans last month.

So we can say that;

Now we know that;

Totaled amount of sales last month is equal to the number of casual jeans sold multiplied by Cost of casual jeans plus the number of dress jeans sold multiplied by Cost of Dress jeans.

framing in equation form we get;

Now Substituting the equation 1 in equation 2 we get;

Dividing both side by 260; Using Division property we get;

Now Substituting the value of 'y' in equation 1 we get;

Hence Banana Republic at the Orlando, Florida, outlet store sold 125 casual jeans and 25 Dress jeans last month.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.