Translate the following application into an algebraic equation: "at a hot dog eating contest, andy ate 5 more than barry, while carl ate 10 less than barry. if the three ate a total of 103 hot dogs, how many did each eat? "

Andy ate 41 hot dogs

Barry ate 36 hot dogs

Carl ate 26 hot dogs

Step-by-step explanation:

Let the quantity of hot dogs eaten by Andy, Barry and Carl be A, B and C respectively.

Andy ate 5 more than Barry =>

A = B + 5. (Equation i)

Carl ate 10 less than Barry =>

C = B - 10. (Equation ii)

The three atr the total or 103 hot dogs.

ie. A + B + C = 103 (Equation iii)

From i and ii, substitute (B + 5) for A and (B - 10) for C in equation (iii)

(B + 5) + B + (B - 10) = 103

B + 5 + B + B - 10 = 103

B + B + B + 5 - 10 = 103

3B - 5 = 103

3B = 103 + 5

3B = 108

B = 108/3

B= 36

From equation (i)

A = B + 5

A = 36 + 5

A = 41

From equation (ii)

C = B - 10

C = 36 - 10

C = 26

Andy ate 41 hot dogs

Barry ate 36 hot dogs

Carl ate 26 hot dogs

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