Coach smith created an activity course for her students. the length of the course she created is 616.25 feet long, and there are five obstacles. the course will be completed in teams with five members on each team. each team member must run a section and do an obstacle. if each obstacle is 20.75 feet long and the distance each student must run is the same, how far must each team member run?

each team member run 123.25 feet

Step-by-step explanation:

The length of the course she created is 616.25 feet long, and there are five obstacles. If each obstacle is 20.75 feet long, it means that the total length of the five obstacles would be

20.75 × 5 = 103.75 feet

The length of the course without an obstacle would be

616.25 - 103.75 = 512.5 feet

The course will be completed in teams with five members on each team. Each team member must run a section and do an obstacle. Since the distance each student must run is the same, then the length of the course without an obstacle that each student would run is

512.5/5 = 102.5

Total length with an obstacle for each student would be

102.5 + 20.75 = 123.25 feet

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.