2. which of the following are the coordinates of the vertices of the following square with sides of length a?

The coordinates of the four vertices are;

O(0,0), W(a, 0), T(a, a), S(0, a)

We can see that point O is at the origin of the axis. Thus;

Coordinate of point O is (0, 0)

We are told that the sides of the square is a.

Thus; OW = OS = WT = ST = a

Thus;

The y coordinate of point S is a

The y coordinate of point T is a

The x coordinate of point W & T is a

The y coordinate of W is 0

Thus, the coordinates of the points are;

O(0,0), W(a, 0), T(a, a), S(0, a)

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The first option: O(0,0) , S(0,a) , T(a,a) , W(a,0)

Step-by-step explanation:

Point O : is the intersection between x-axis and y-axis ⇒ (0,0)

Point W : is falling over the x-axis, OW = length of the square = a ⇒ (a,0)

Point S : is falling over the y-axis, OS = length of the square = a ⇒ (0,a)

Point T : WT = a and SW = a ⇒ (a,a)

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.