Find the equation of the line that contains the point (6, -2) and is perpendicular to the line y.

Equation of the perpendicular line will be .

Step-by-step explanation:

Given question is incomplete ; here is the complete question.

Find the equation of the line that contains the point (6,-2) and is perpendicular to the line y=-2⁢x+8.

Slope of the given line is (-2).

If the slope of the required line is m then,

m × (-2) = (-1) [Slopes of the perpendicular lines when multiplied equals to (-1)]

m =

Now the equation of the line passing through a point (6, -2) with slope will be

y - y' = m(x - x')

y + 2 =

y =

Therefore, equation of the perpendicular line will be