The length of a rectangular field is represented by the expression 14x-3x2 + 2y. the width of the field is represented by the
expression 5x-7x2 + 7y. how much greater is the length of the field than the width?
9x+4x2 - 5y
9x-10x2 - 5y
19x+4x2+9y
19x-10x2 +9y
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36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.