Two cyclists, 90 mi apart, start riding towards each other at the same time. one cycles twice as fast as the other.
if they meet 3 hr later, at what average speed is each cyclist traveling?

Step-by-step explanation:

Distance between cyclists = 90 miles

Let v be the speed of one cyclist, speed of other cyclist is twice the speed of first cyclist.

Speed of second cyclist = 2 x v

Time taken by them to meet = 3 hr

Since they are moving towards each other, relative velocity is given by

                Relative velocity = v + 2v = 3v

We have

       Distance = Time x Velocity

       90 = 3 x 3 v

           9v = 90

             v = 10 mile per hour

Speed of cyclist 1 = v = 10 mile per hour

Speed of cyclist 2 = 2v = 20 mile per hour

a

b

d

step-by-step explanation: