Determine whether the function is continuous or discontinuous at xr=1. examine the
three conditions in the definition of continuity.
fx2+8 if x< 1
f(x)
= 6x2 — 3 if x> 1



1. f(x) is continuous at x = 1

2. f(x) is continuous at x = 1

Step-by-step explanation:

Determine whether the function is continuous or discontinuous at x=1.

Examine the three conditions in the definition of continuity.

1. f(x) = x²+8 if x<1

2. f(x) = 6x² - 3 if x> 1

For a function to be continuous at a given x-value

then lim x→a f(x) = f(a)

Meaning that

What this is saying is that, as x gets closer to a , f(x) should also get closer to f(a).

1. Limit of f(x) = x² + 8 at x = 1

= 1²+8 = 9

f(a) = f(1) = 1² + 8 = 9.

lim x→a f(x) = f(a) = 9

2. Limit of f(x) = 6x² - 3 at x = 1

= 6(1²) - 3 = 3

f(a) = f(1) = 6(1²) - 3 = 3

lim x→a f(x) = f(a) = 3

1/2*qr*rs

step-by-step explanation:

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