Radioactive decay beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining after t years is given by
y=16(1/2)^t/30 ,t ≥ 0.
how much of the initial mass remains after 90 years?

2 grams of the initial mass remains after 90 years.

Step-by-step explanation:

The initial amount of the radioactive element is 16 grams. The half-life of the radioactive element is 30 years.

The mass y(in grams) remaining after t years is given by

y=16(1/2)^t/30 ,t ≥ 0

Therefore, the amount of the initial mass that remains after 90 years would be

y=16(1/2)^90/30

y=16(1/2)^3

y = 16 × 0.125 = 2 grams

$79500

step-by-step explanation:

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: