Pumping alone at respective constant one inlet pipe fills an empty tank to 1/2 of capacity in 3 hours and a second inlet pipe fills the same empty tank to 2/3 of capacity in 6 hours.
how many hours will it take both pipes, pumping simultaneously at their respective constant rates, to fill the empty tank to capacity?
a. 3.25
b. 3.6
c. 4.2
d. 4.4
e. 5.5

B. 3.6

Step-by-step explanation:

Given : Time taken by one inlet pipe to empty of tank =  3 hours

⇒ Time taken by one inlet pipe to empty tank (entire) =  2 x 3 hours

= 6 hours →

Time taken by  second inlet pipe to empty of tank =  6 hours

⇒ Time taken by second inlet pipe to empty tank (entire) =

= 9 hours  →

If both pipes are pumping simultaneously at their respective constant rates to fill the empty tank to capacity.

Then time taken by them to fill the empty tank to capacity would be  

Hence, it will take 3.6 hours to fill the empty tank to capacity .

Therefore , the correct answer is  B. 3.6 .

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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