How much candy at $1.20 a pound should be mixed with candy worth 95¢ a pound in order to obtain a mixture of 50 pounds of candy worth a dollar a pound?

10 pounds of candy worth $1.20 per pound should be mixed with 40 pounds of candy worth 95¢ per pound

Step-by-step explanation:

Let

x ----> pounds of candy worth at $1.20 a pound

y ----> pounds of candy worth at 95¢ a pound

we know that

The pounds of candy worth at $1.20 a pound plus the pounds of candy worth at 95¢ a pound must be equal to 50 pounds of candy worth a dollar a pound

so

The linear equation that represent this situation

----> equation A

----> equation B

solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

using a graphing tool

The solution is the point (10,40)

see the attached figure

therefore

10 pounds of candy worth $1.20 per pound should be mixed with 40 pounds of candy worth 95¢ per pound

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure

you have to put the graph on here with the question

step-by-step explanation: