Hello everyone!
can you me with this math activity? would be very appreciated.

the area of a rectangle is . state the dimensions of the rectangle with the least perimeter. calculate the perimeter.

Dimensions are 6√2 by 6√2 and perimeter = 24√2.

Step-by-step explanation:

Let p by q gives the dimensions of the rectangle.

So, length = p and width is q.

Now, given that area of the rectangle is, A = pq = 72 ......... (1)

Now, P = 2(p + q) .......... (2) gives the perimeter of the rectangle.  

⇒ {From equation (1)}

Now, condition for perimeter to be maximum is  

⇒ q² = 72

⇒ q = 6√2

Therefore, from equation (1) .

So, the perimeter, P = 2(6√2 + 6√2) = 24√2. {From equation (2)}

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide