Aperson has a 35 percent chance of winning on a scratch off lottery ticket. what is the probability she first wins of he sixth ticket?

a.(0.65)^3(0.35)
b.(6/3)(0.65)^3(0.35)
c.(0.35)^3(0.65)
d, (6/1)(0.35)^3(0.65)
e. 0.35

None of the options are correct

Step-by-step explanation:

Given :

a person has 35% chance of winning on a scratch- off lottery ticket.

To find the probability that she wins  the sixth ticket is,

P( she first wins the sixth ticket )

= _ _ _ _ _ _

the first 5 dashes represent does not win values ( prob = 0.65)

the last dash represents the win ( prob = 0.35)

= (0.65) ^5 * 0.35                          {assuming independence

none of the option is correct.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

there is no question content here, but you for the free points! : d