Which point would be a solution to the system of linear inequalities ?

(12,-6)

Step-by-step explanation:

we have

----> inequality A

---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

Verify each point

Substitute the value of x and the value of y  of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

----> is true

Inequality B

----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

----> is true

Inequality B

----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

----> is true

Inequality B

----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

----> is true

Inequality B

----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

step-by-step explanation:

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6