Suppose that there are two types of tickets to show: advance and same-daythe combined cost of one advance ticket and one same-day ticket is $55. for one performance, 25 advance tickets and 30 same-day tickets were sold. the total amount paid for the tickets was $1450 . what was the price of each kind of ticket?

the price of one advance ticket is $40

the price of one same day ticket is $15

Step-by-step explanation:

Let x represent the price of one advance ticket.

Let y represent the price of one same day ticket.

The combined cost of one advance ticket and one same-day ticket is $55. This means that

x + y = 55

For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1450. This means that

25x + 30y = 1450 - - - - - - - - -1

Substituting x = 55 - y into equation 1, it becomes

25(55 - y) + 30y = 1450

1375 - 25y + 30y = 1450

- 25y + 30y = 1450 - 1375

5y = 75

y = 75/5 = 15

Substituting y = 15 into x = 55 - y, it becomes,

x = 55 - 15

x = 40

hello umm i don't understand your question can you explain it more pls

step-by-step explanation:

im guessing (23,14). hope this : )