Awater well drilling rig has dug to a height of -15 feet in three hours. if the rig has been running constantly and is currently at a height of -192.5 feet, for how long has the rig been running? group of answer choices

answer: 38.5 hours

step-by-step explanation:

running constantly means the rate of change( gradient ) is constant. so this can be modelled with equation h = mt + c.(where h is height dug and t is time taken)

since you will start digging from the surface, y-intercept will be zero.

now it becomes h = mt.

now to find m, do -15/3 = -5 because to find the rate at which the well is being dug. now equation becomes h = -5t.

now,

-192.5 = -5t

-192.5/-5 = t

t = 38.5 hours

0.6

39mph

step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value