These marbles are placed in a bag and two of them are randomly drawn what is the probability of drawing two yellow marbles if the first one is placed back before the second draw. write your answer as a ratio. reduce to simplest terms

Probability of drawing two yellow marbles if the first one is placed back before the second draw is 1 : 5.

Step-by-step explanation:

Given:

Number of yellow marbles  = 2

Number of pink marbles  = 3

Number of blue marbles  = 5

Total number of marbles = 10

To Find:

Probability of drawing two yellow marbles if the first one is placed back before the second draw = ?

Solution:

Let

P(A)  be the probability of drawing the first marble

P(B) be the probability of drawing the second marble.

Similarly

Since the first one is placed back before the second draw.

Now  P(A) and  P(B) are independent event

=>

=>

=>

=>

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )