Asound wave travels through iron at a rate of 5120\,\dfrac{\text{m}}{\text{s}}512 0
s
m

5120, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction.
at what rate does the sound wave travel in \dfrac{\text{km}}{\text{h}}
h
km

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

step-by-step explanation:

im not sure what the answer is