Write an equation of the perpendicular bisector of the segment with endpoints a(-2 0) and r(6 12)

 y = - 2/3 x + 7 1/3

Step-by-step explanation:

coordinate of midpoint of ar   (difference of x/2, difference of y/2)

= -2 +(6 - (-2))/2 , 0 + (12 - 0) / 2) = (2 , 6)

slope of ar = (12 - 0) / (6 - (-2)) = 12 / 8 = 3/2

slope of perpendicular line = - 2/3

For line pass (2, 6)    y = mx + b    m= - 2/3

b = y - mx = 6 - (- 2/3) x 2 = 22/3

equation: y = - 2/3 x + 7 1/3

check: (2 , 6)      y = (-2/3) x 2 + 7 1/3 = - 4/3 + 22/3 = 18/3 = 6

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft