How much would you have to
deposit today to end up with
$1000 in 10 years if yearly
interest is 6% compounded
quarterly?

The principal sum to be deposited is $ 551.26

Solution:

Given that,

Amount after 10 years = $ 1000

Rate of Interest = 6 % compounded quarterly

Number of years = 10 years

Principal = ?

The formula for compound interest, including principal sum, is:

Where,

A = the future value of the investment/loan, including interest

P = the principal investment amount (the initial deposit or loan amount)

r = the annual interest rate (decimal)

n = the number of times that interest is compounded per unit t

t = the time the money is invested or borrowed for

Since interest is compounded quarterly, n = 4

Substituting the values in formula,

Thus the principal sum to be invested is $ 551.26

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: