Can someone me find areas of similar figures. ill give brainlest and points

Therefore the Area of ΔEDF is 9.6 in².

Step-by-step explanation:

Given:

ΔBAC ~ ΔEDF

EF = 4 in

BC = 5 in

Area of ΔBAC = 15 in²

To Find:

Area of ΔEDF = ?

Solution:

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.

This proves that the ratio of areas of two similar triangles is proportional to the squares of the corresponding sides of both the triangles.

ΔBAC ~ ΔEDF  ........Given

Therefore we will have

Substituting the values we get

Therefore the Area of ΔEDF is 9.6 in².

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24