Abasketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. she misses the first shot 40% of the time. when she misses the first shot, she misses the second shot 5% of the time.
part a: what is the probability of missing both free-throw shots?
part b: what is the probability of making at least 1 free-throw shot?

The probability of missing both free-throw shots = 2%

The probability of making at least 1 free-throw shot = 98%

Step-by-step explanation:

Given :

Probability that she misses the first shot  = 40%

Probability she misses the second shot  = 5%

Solution:

Part A: The probability of missing both free-throw shots:

The two shots are independent events so, we can use rule of independent events

=>

=>

=>

=>

=>

Part B: The probability of making at least 1 free-throw shot

Probability of making at least 1 free throw show shot = 1 - probability of miss both the shots

=>

=>

=>

=>

honesty mood

step-by-step explanation: