For two events a and b show that p (a∩b) ≥ p (a)+p (b)−1.
(hint: apply de morgan’s law...
Mathematics, 10.01.2020 03:31 stacy021603
For two events a and b show that p (a∩b) ≥ p (a)+p (b)−1.
(hint: apply de morgan’s law and then the bonferroni inequality).
derive below results 1 to 4 from axioms 1 to 3 given in section 2.1.2 in the textbook.
result 1: p (ac) = 1 − p(a)
result 2 : for any two events a and b, p (a∪b) = p (a)+p (b)−p (a∩b)
result 3: for any two events a and b, p(a) = p(a ∩ b) + p (a ∩ bc)
result 4: if b ⊂ a, thena∩b = b. therefore p (a)−p (b) = p (a ∩ bc) and p (a) p(b).
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