Two cyclists start at the same point and travel in opposite directions. one cyclist travels 10 mih slower than the other. if the two cyclists are 104 miles apart after 4 hours, what is the rate of each cyclist?

The speed of slower cyclist is 8 miles per hour

The speed of faster cyclist is 18 miles per hour

Solution:

One cyclist travels 10 min slower than the other

Let "x" be the speed of slower cyclist

Then, x + 10 is the speed of faster cyclist

The distance is given by formula:

Distance of slower cyclist =

Distance of slower cyclist = 4x

Distance of faster cyclist =

The two cyclists are 104 miles apart after 4 hours

4x + 4x + 40 = 104

8x + 40 = 104

8x = 104 - 40

8x = 64

x = 8

Thus rate of each cyclist is:

speed of slower cyclist = x = 8 miles per hour

speed of faster cyclist = x + 10 = 8 + 10 = 18 miles per hour

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof

12r - 8 - 12

you have to combine like terms. below i have bolded the like terms:

12r - 8 - 12

together it combines to:

12r - 20

hope this !