For the fundraiser, will sole 225 candy bars. he earns $1 for each almond candy bar he sells and $0.75 for each caramel candy bar he sells. if he earned a total of $187.50, how many of each type of candy bar did he sell for the fundraiser?

Fundraiser sold 150 caramel candy bars and 75 almond candy bars

Solution:

Let "c" be the number of caramel candy bars sold

Let "a" be the number of almond candy bars sold

Cost of 1 caramel candy bar = $ 0.75

Cost of 1 almond candy bar = $ 1

He sold 225 candy bars. Therefore, we can frame a equation as;

number of caramel candy bars sold + number of almond candy bars sold = 225

c + a = 225 ----- eqn 1

He earned a total of $ 187.50. Therefore, we can frame a equation as;

number of caramel candy bars sold x Cost of 1 caramel candy bar + number of almond candy bars sold x Cost of 1 almond candy bar = 225

0.75c + a = 187.5 --------- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

c = 225 - a ------ eqn 3

Substitute eqn 3 in eqn 2

0.75(225 - a) + a = 187.5

168.75 - 0.75a + a = 187.5

0.25a = 18.75

a = 75

Substitute a = 75 in eqn 3

c = 225 - 75

c = 150

Thus he sold 150 caramel candy bars and 75 almond candy bars

number one is the correct answer

step-by-step explanation: dogs and cats are mentioned, no other animals

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.