< coa = 150 ( given)
as ba and bc are tangents
so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre
so in quadrilateral oabc
< coa + < oab + < ocb + < abc = 360
150 +90+90 + < abc = 360
330 + < abc = 360
< abc = 360 -330 = 30
so < abc = 30
⭐dhruv⭐
i found two solutions, n = 2 • ± √3 = ± 3.4641
step-by-step explanation:
40 minutes
add the time and multiply by 2