Mathematics, 09.01.2020 07:31 gabby4623

1.
a. write an equation of the line that passes through the origin that intersects the line 2x + 5y = 7 to form a
right angle.
b. determine whether the lines given by the equations 2x + 3y = 6 and y = 3 / 2 x + 4 are perpendicular. support
your answer.
c. two lines having the same yy-intercept are perpendicular. if the equation of one of these lines is y = − 4 / 5 x + 6,
what is the equation of the second line?

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Answer from: UltimateGoal

a) $y=\dfrac{5}{2}x$

b) yes the two lines are perpendicular

c) $y=\dfrac{5}{4}x+6$

Step-by-step explanation:

a) All this is asking if to find a line that is perpendicular to 2x + 5y = 7 AND passes through the origin.

so first we'll find the gradient(or slope) of 2x + 5y = 7, this can be done by simply rearranging this equation to the form y = mx + c

5y = 7 - 2x

$y = \dfrac{7 - 2x}{5}$

$y = \dfrac{7}{5} - \dfrac{2}{5}x$

$y = -\dfrac{2}{5}x+\dfrac{7}{5}$

this is changed into the y = mx + c , and we easily see that -2/5 is in the place of m, hence $m = \frac{-2}{5}$ is the slope of the line 2x + 5y = 7.

Now, we need to find the slope of its perpendicular. We'll use:

m_1m_2=-1 .

here both slopes m_1 and m_2 are slopes that are perpendicular to each other, so by plugging the value -2/5 we'll find its perpendicular!

$\dfrac{-2}{5}m_2=-1$ .

$m_2=\dfrac{5}{2}$ .

Finally, we can find the equation of the line of the perpendicular using:

(y-y_1)=m(x-x_1)

we know that the line passes through origin(0,0) and its slope is 5/2

$(y-0)=\dfrac{5}{2}(x-0)$

$y=\dfrac{5}{2}x$ is the equation of the the line!

b) For this we need to find the slopes of both lines and see whether their product equals -1?

mathematically, we need to see whether m_1m_2=-1 ?

the slopes can be easily found through rearranging both equations to y=mx+c

Line:1

2x + 3y =6

$y =\dfrac{-2x+6}{3}$

$y =\dfrac{-2}{3}x+2$

Line:2

$y = \dfrac{3}{2}x + 4$

this equation is already in the form we need.

the slopes of both equations are

$m_1 = \dfrac{-2}{3}$ and $m_2 = \dfrac{3}{2}$

using

m_1m_2=-1

$\dfrac{-2}{3} \times \dfrac{3}{2}=-1$

-1=-1

since the product does equal -1, the two lines are indeed perpendicular!

c)if two perpendicular lines have the same intercept, that also means that the two lines meet at that intercept.

we can easily find the slope of the given line, y = − 4 / 5 x + 6 to be $m=\dfrac{-4}{5}$ and the y-intercept is c=6 the coordinate at the y-intercept will be (0,6) since this point only lies in the y-axis.