3. a gallup poll reported that 28% of adults (age 18 and older) eat at a fast food restaurant about once a week. find the probability that two randomly selected adults would both say they
eat at a fast food restaurant about once a week.

0.0784 or 7.84%

Step-by-step explanation:

Data provided in the question:

Probability that adults (age 18 and older) eat at a fast food restaurant about once a week, P(F) = 28% = 0.28

Now,

Probability that two randomly selected adults would both say they  eat at a fast food restaurant about once a week

= First adult selected eats fast food × Second adult selected eats fast food

= 0.28 × 0.28

= 0.0784

or

= 0.0784 × 100%

= 7.84%

i just took the test, the correct answer is .. 31.5 in.

probably .5

i can on others if necessary.