Have two hats. in one hat are balls numbered 1 through 15. in the other hat are balls numbered 16 through 25. i first choose a hat, then from that hat, i choose 3 balls, without replacing the balls between selections. how many different orders selections of 3 balls are possible?

3450 ways

Step-by-step explanation:

Different ways of picking 3 balls from the 1st hat:

1st ball: 15 choices (because there are 15 balls)

2nd ball: 14 choices (because one ball is taken away)

3rd ball: 13 choices (because two ball is taken away)

15*14*13=2730 different possible orders of picking 3 balls from the 1st hat

Different ways of picking 3 balls from the 2nd hat:

1st ball: 10 possibilities (because there are 10 balls)

2nd ball: 9 possibilities

3rd ball: 8 possibilities

10*9*8=720 different possible orders of picking 3 balls from the 2nd hat

720+2730=3450

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!