Agame is played by drawing a single card from a regular deck of playing cards. if you get a black card, you win
nothing. if you get a diamond, you win $5.00. if you get a heart, you win $10.00. how much would you be willing
to pay if the game is to be fair? explain.

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

Solution to the problem

For this case we need to use the definition of expected value given by:

For this case we need that the expected value would be 0 since we want a fair game.

Assuming a standard deck of 52 cards. We can find the probabilities for each possible event.

And we have the following values:

Let A the amount that we need to pay for a game we have this equality:

And if we solve for A we got:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

plz mark brainliest i took the test