Find the maximum rate of change of f(x, y) = x2y +2y
at the point (-1,2) and the direction in which it occurs.

Maximum rate of change at the point (-1,2) = √17

Direction is the direction of the gradient

Step-by-step explanation:

The gradient of a function (scalar or vectorial ) is a vector in the direction of maximum rate of change then

f( x,y ) =  x*2y  + 2y

grad    =  δ/δx i +  δ/δy j + δ/δz k

grad f(x,y)  = [ δ/δx i , δ/δy]  =  [ 2y , x+2 ]

at the point  ( -1 , 2 )

grad f(x,y)  = [4 , 1]

| grad f(x,y) |  =  √ (4)²  + (1)²   =  √17

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)