Acircular swimming poolwith a diameter of 28 feet has
a deck ofuniform width built around it. if the area of the deckis
60(pi) square feet, find its width.

2 feet

Step-by-step explanation:

Let 'w' be twice the width of the deck.

The area of the swimming pool is:

The area of the swimming pool plus the deck is:

Therefore, the area of the deck is given by:

Solving the quadratic equation:

Since the width cannot be negative, w = 4 feet, ad the width is 2 feet.

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.

50- 250 is correct i did that one too

step-by-step explanation: