Mathematics, 08.01.2020 23:31 Michcardwell8570
Use a half -angle formula to find sin pi/8 exactly.
Answers: 1
you must:
![\frac{1-\frac{\sqrt{2}}{2}}{2}=\frac{2-\sqrt{2}}{4}\\\\\sqrt{\frac{2-\sqrt{2}}{4}}\\\\\mathrm{Apply\:radical\:rule\:}\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}\\\\\frac{\sqrt{2-\sqrt{2}}}{\sqrt{4}}\\\\\frac{\sqrt{2-\sqrt{2}}}{2}](/tpl/images/0447/5171/41e06.png)
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Use a half -angle formula to find sin pi/8 exactly....
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