An aluminum alloy containing 48% aluminum is to be made by containing 30% and 60% alloys. how many pounds of the 60% alloy must be added to 24 pounds of the 30% alloy to produce the desired aluminum alloy?

36 pounds

Step-by-step explanation:

48% = 48/100 = 0.48

30% = 30/100 = 0.3

60% = 60/100 = 0.6

Let pounds of 60% alloy added = x

So, from the statement, we can write:

0.6x + 0.3(24) = 0.48(x + 24)

Note "x + 24" in total because we are adding "x" from 60% and "24" from 30% alloys.

Now, we have to solve the above equation for x:

Thus,

We would need 36 pounds added from 60% alloy

sine

step-by-step explanation: