10. selecting marbles a bag contains 9 red marbles,
8 white marbles, and 6 blue marbles. randomly choose
two marbles, one at a time, and without replacement.
find the following.
a. the probability that the first marble is red and the
second is white
b. the probability that both are the same color
c. the probability that the second marble is blue

a) The probability that the first marble is red and the second is white.

P = (9/23)(8/22)

b) The probability that both are the same color.

P = 2R + 2W + 2B

P = (9/23)(8/22) + (8/23)(7/22) + (6/23)(5/22)

c) The probability that the second marble is blue.

P = (17/23)(6/22) + 2B (Need to consider both are Blue)

P = .202 + (6/23)(5/22) = .202 + .059 = .261

23 marbles

9/23*8/22, since there is one less marble

That is 72/506 or 0.142

same color

9/23*8/22 (red)

8/23*7/22 (white)

6/23*5/22 (blue)

The denominator is 506

The numerator is 72+56+30=158

158/506=0.312

Second marble blue:

3 possibilities

first red and then it is 9/23*6/22

first blue and then it is 6/23*5/22

first is white and then it is 8/23*6/22

Denominator is 506

Numerator is 54+30+48=132

132/506=0.261

Step-by-step explanation:

step-by-step explanation:

answer: none of these answers are correct only the second half is

step-by-step explanation: