What is an equation of the line that passes through (0, 8) and (4, 0)?

a. y = -2 x + 8
b. y = -2 x + 4
c. y = 2 x + 8
d. y = 2 x + 4

Step-by-step explanation:

first thing we do is find the slope by using ur 2 points and the slope formula

slope = (y2 - y1) / (x2 - x1)

(0,8)...x1 = 0 and y1 = 8

(4,0)...x2 = 4 and y2 = 0

now we sub

slope = (0 - 8) / (4 - 0) = -8/4 = -2

so we have a slope of -2

now we use y = mx + b and either one of ur points...m represents the slope

y = mx + b

slope(m) = -2

(0,8)x = 0 and y = 8

now sub...we are looking for b, the y int

8 = -2(0) + b

8 = 0 + b

8 = b

so ur equation is : y = -2x + 8 <===

u can check this by subbing in either of ur points into ur equation to see if its true.

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

y=1/4x-4

step-by-step explanation: